Tolong dibantu no.6 saja
Matematika
BrilianSaja123
Pertanyaan
Tolong dibantu no.6 saja
1 Jawaban
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1. Jawaban mhaidarfh02
[tex]\sqrt{64}. ( \sqrt[3]{1728} - 2^{3} ) / \sqrt[3]{2744} = \sqrt{ 2^{6} } . ( \sqrt[3]{ 3^{3}. 2^{6} } - 2^{3} )/ \sqrt[3]{ 2^{3}. 7^{3} } [/tex]
= 2².(12 - 8) /7
= 4.4/7
= 16/7
= 2 2/7