integral dt/4t2+49 Diselesaikan dengan substitusi trigonometri!

Integral.

∫ dt / (4t² + 49)
at² + b = 4t² + 49
u = at / b
   = 2t / 7
du / dt = 2/7 → dt = 7du / 2

∫ dt / (4t² + 49)
= 7/2 ∫ du / (49u² + 49)
= 1/14 ∫ du / (u² + 1)
= 1/14 arctan u + C
= 1/14 tan⁻¹ (2t / 7) + C