lim x=0 sin3x-sin3xcosx/2x^3
Matematika
muhammadit
Pertanyaan
lim x=0 sin3x-sin3xcosx/2x^3
1 Jawaban
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1. Jawaban DB45
Limit
limit (x -> 0) sin 3x ( 1 - cos x) / (2x³)
limit (x ->0) sin 3x (- 2 sin² (1/2 x)) / (2x³)
limit (x ->0) - 2 sin 3x . sin 1/2 x . sin 1/2 x / (2 x³)
= (-3)(1/2)(1/2) / (2)
= - 3/2 (1/4)
= - 3/8