yang g ,tolobg dijawab ,makasih

[tex]\displaystyle \frac{12}{x^2-9}:\frac{3}{x+3} \\ \frac{12}{(x+3)(x-3)}\times \frac{x+3}{3} \\ \\ \frac{4}{x-3}[/tex]

12/x^2 -9 : 3/x+3
12/(x+3)(×-3) : 3/×+3
12/(×+3)(×-3) × ×+3/3
4/(×-3)