Matematika

Pertanyaan

integral(3-x)/√x^2-6x+3 dx pakai jalan yaa tolong..

1 Jawaban

  • Konsep integral u udu
    Mis u =x^2-6x+3
    Du/dx = 2x-6
    Dx= du/ 2x-6
    Integral(3-x)/√x^2-6x+3 dx = Integral(3-x)/ u ^(-1/2)× du/2x-6=
    Integral(3-x)/ u ^(-1/2)× du/-2 (3 -x)=
    Integral -1/2u ^(-1/2)× du
    -1/2 ×2 u^1/2+c=
    -1 ( √x^2-6x+3 )+c


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