integral(3-x)/√x^2-6x+3 dx pakai jalan yaa tolong..
Matematika
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Pertanyaan
integral(3-x)/√x^2-6x+3 dx pakai jalan yaa tolong..
1 Jawaban
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1. Jawaban Murva
Konsep integral u udu
Mis u =x^2-6x+3
Du/dx = 2x-6
Dx= du/ 2x-6
Integral(3-x)/√x^2-6x+3 dx = Integral(3-x)/ u ^(-1/2)× du/2x-6=
Integral(3-x)/ u ^(-1/2)× du/-2 (3 -x)=
Integral -1/2u ^(-1/2)× du
-1/2 ×2 u^1/2+c=
-1 ( √x^2-6x+3 )+c