jika X=32 dan Y=27, tentukan nilai dari 5Y^4/3 : X^6/5
Matematika
lisajuliana43
Pertanyaan
jika X=32 dan Y=27, tentukan nilai dari 5Y^4/3 : X^6/5
2 Jawaban
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1. Jawaban Zila1213
5(27)^4/3 : 32^6/5
= 5(3³)^4/3 : (2^5)^6/5
= 5(3⁴) : 2^6
= 5(81) : 64
= 405 : 64
= 6,33 -
2. Jawaban Sutr1sn0
x = 32
y = 27
5y^4/3 : x^6/5
= 5(27^4/3) : (32^6/5)
= 5((3^3)^4/3) : (2^5)^6/5
= 5(3^(3×4/3)) : (2^(5×6/5))
= 5(3^4) : 2^6
= 5(81) : 64
= 405 : 64
= 6 21/64