Bantu jawab !!! 2 soal

1][

Misal :
2'log x = a
x'log 8 = x'log 2^3 = 3/a

2'log x + x'log 8 = 4
a + 3/a = 4 ... kali a
a² - 4a + 3 = 0
(a - 1)(a - 3) = 0
a = 2'log x = 1 ---> x = 2
atau
a = 2'log x = 3 ---> x = 2^3 = 8

HP = {2 , 8}

2][
(3x + 2)'log 27 = 5'log 3
(3x + 2)'log 3^3 = 5'log 3
3 . (3x + 2)'log 3 = 5'log 3
5'log (3x + 2) = 3
3x + 2 = 5^3
3x + 2 = 125
3x = 125 - 2
x = 123/3
x = 41