tentukan himpunan dari 2x^2-9x-5=0 dengan cara Faktorisasi, MKS, dan Rumus ABC..!!

▶ Memfaktorkan
2x² - 9x - 5 = 0
2x² + x - 10x - 5 = 0
x(2x + 1) - 5(2x + 1) = 0
(x - 5)(2x + 1) = 0
x = 5 atau x = -1/2

▶ Rumus abc
2x² - 9x - 5 = 0
a = 2
b = -9
c = -5

x1.2 = (-b ± √(b² - 4ac))/2a
x1.2 = (9 ± √(9² - 4(2)(-5))/(2.2)
x1.2 = (9 ± √121)/4
x1.2 = (9 ± 11)/4
x1 = (9 + 11)/4 = 5
x2 = (9 - 11)/4 = -2/4 = -1/2

▶ Melengkapkan Kuadrat Sempurna
2x² - 9x = 5
(√2 x - 9/(2√2))² = 5 + (9/(2√2))²
(√2 x - 9/(2√2))² = 5 + 81/8
(√2 x - 9/(2√2))² = 121/8
√2 x - 9/(2√2) = √(121/8)
√2 x - 9/(2√2) = ± 11/(2√2) ... ( × √2 )
2x - 9/2 = ± 11/2
2x = 9/2 ± 11/2 ... ( : 2 )
x = (9 ± 11)/4
x1 = (9 + 11)/4 = 5
atau
x2 = (9 - 11)/4 = -1/2

HP = {-1/2 , 5}