faktorkanlah! 1. x²-5x-14 = 2. a²+3a-10 = 3. m²-7m+12 = 4. p²-6pq-16q² = pliss jwb yaa! mksh :))
Matematika
sylfiaanggraeni1
Pertanyaan
faktorkanlah!
1. x²-5x-14 =
2. a²+3a-10 =
3. m²-7m+12 =
4. p²-6pq-16q² =
pliss jwb yaa! mksh :"))
1. x²-5x-14 =
2. a²+3a-10 =
3. m²-7m+12 =
4. p²-6pq-16q² =
pliss jwb yaa! mksh :"))
2 Jawaban
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1. Jawaban TamaraSep
1.
x2 - 5x - 14 = (x-7)(x+2)
x -7
x 2
2.
a2 + 3a - 10 = (a+5)(a-2)
a 5
a -2
3.
m2 - 7m + 12 = (m-3)(m-4)
m -3
m -4
4.
p2 - 6pq - 16q2 = (p-8q)(p+2q)
p -8q
p 2q
Maaf kalo caranya kurang bisa dipahami -
2. Jawaban sayadevi131
1) x2-5x-14=0
= (x-7) (x+2) =0
X=7 atau x=-2
2). a2+3a-10=0
= (x+5) (x-2) =0
X=-5 atau x=2
3) m2-7m+12=0
= (m-4) (m-3) =0
M=4 atau m=3
4). p2-6pq-16q2=0
= (p-8q) (p+2q)
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