nyatakan dalam perbandingan trigonometri sudut lancip: 1. sin 250 2. cos 320 3. tan 160 4. cot 130 5. sec 273 6. cosec 350
Matematika
tie
Pertanyaan
nyatakan dalam perbandingan trigonometri sudut lancip:
1. sin 250
2. cos 320
3. tan 160
4. cot 130
5. sec 273
6. cosec 350
1. sin 250
2. cos 320
3. tan 160
4. cot 130
5. sec 273
6. cosec 350
1 Jawaban
-
1. Jawaban MathTutor
Kategori Soal : Matematika - Trigonometri
Kelas : X (1 SMA)
Pembahasan :
Pembagian sudut dalam trigonometri.
Dalam trigonometri, besar sudut α dibagi menjadi 4 kelompok, yaitu :
Kuadran I : 0° < α < 90° (0 < α < π/2)
sin (90° - α) = cos α
cos (90° - α) = sin α
tan (90° - α) = cotan α
cotan (90° - α) = tan α
secan (90° - α) = sec α
sec (90° - α) = cosec α
Kuadran II : 90° < α < 180° (π/2 < α < π)
sin (180° - α) = sin α
cos (180° - α) = -cos α
tan (180° - α) = -tan α
cotan (180° - α) = -cotan α
secan (180° - α) = secan α
sec (180° - α) = -sec α
Kuadran III : 180° < α < 270° (π < α < 3π/2)
sin (270° - α) = -cos α
cos (270° - α) = -sin α
tan (270° - α) = cotan α
cotan (270° - α) = tan α
secan (270° - α) = -sec α
sec (270° - α) = -cosec α
Kuadran IV : 270° < α < 360° (3π/2 < α < 2π)
sin (360° - α) =sin (-α) = -sin α
cos (360° - α) = cos (-α) = cos α
tan (360° - α) = tan (-α) = -tan α
cotan (360° - α) = cotan (-α) = -cotan α
secan (360° - α) = secan (-α) = -secan α
sec (360° - α) sec (-α) = sec α
Mari kita lihat soal berikut.
1. sin 250° = -cos (3 x 90 - 20)° = -cos 20°
2. cos 320° = cos (4 x 90 - 40)° = cos 40°
3. tan 160° = -tan (2 x 90 - 20)° = -tan 20°
4. cotan 130° = -cotan (2 x 90 - 50)° = -cotan 50°
5. sec 273° = sec (4 x 90 - 87)° = sec 87°
6. cosec 350° = -cosec (4 x 90 - 10)° = -cosec 10°
Semangat!