Ini cara dan jawabnya gimana?

1. V = int [0 - 4] [(x/2)² - (2√x)²] dx

2. V = 2 int [0 - 1] ((-x² + 2)² - (x²)²) dx

3. pakai parsial

4. int (2x + 1)√(x² + x + 1) dx
misal: u = x² + x + 1
du = 2x + 1 dx
maka int (2x + 1)√(x² + x + 1) dx
= int √u du
= (2/3)u√u + c
= (2/3)(x² + x + 1)√(x² + x + 1) dx

ket: [a - b]
batas bawah = a
batas atas = b